x, y \(\in\) N
Xét : (x + 1) . (2y - 5) = 143 = 13 . 11 = 11 . 13 = 143 . 1 = 1 . 143
TH1 :
\(\left\{{}\begin{matrix}x+1=13\\2y-5=11\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=12\\y=8\end{matrix}\right.\)
TH2 :
\(\left\{{}\begin{matrix}x+1=11\\2y-5=13\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=10\\y=9\end{matrix}\right.\)
TH3 :
\(\left\{{}\begin{matrix}x+1=143\\2y-5=1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=142\\y=3\end{matrix}\right.\)
TH4 :
\(\left\{{}\begin{matrix}x+1=1\\2y-5=143\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=0\\y=74\end{matrix}\right.\)
Vậy .................... (tự kết luận)
