\(-x+\sqrt{x+1}+2\sqrt{x+2}=0\)
\(\Leftrightarrow-x+\left(\sqrt{x+1}\right)^2+2\left(\sqrt{x+2}\right)^2=0\)
\(\Leftrightarrow-x+x+1+2\left(x+2\right)=0\)
\(\Leftrightarrow-x+x+1+2x+4=0\)
\(\Leftrightarrow1+2x+4=0\)
\(\Rightarrow2x=-5\)
\(\Rightarrow x=-\dfrac{5}{2}\)
Vậy.............................................
Tìm x:
a.\(\sqrt{4-\sqrt{4+x}}=x\)
b.\(4\left(\sqrt{x-1}-3\right)x^2+\left(13\sqrt{x+1}-8\right)x-4\sqrt{x-1}-3=0\)
c.\(\sqrt{2x-3}+2\sqrt{x-3}\ge3\sqrt[4]{2x^2+x-6}\)
Giải các phương trình sau:
1) \(\sqrt{3x^2+5x+8}-\sqrt{3x^2+5x+1}=1\)
2) \(x^2-2x-12+4\sqrt{\left(4-x\right)\left(2+x\right)}=0\)
3) \(3\sqrt{x}+\dfrac{3}{2\sqrt{x}}=2x+\dfrac{1}{2x}-7\)
4) \(\sqrt{x}-\dfrac{4}{\sqrt{x+2}}+\sqrt{x+2}=0\)
5)\(\left(x-7\right)\sqrt{\dfrac{x+3}{x-7}}=x+4\)
6) \(2\sqrt{x-4}+\sqrt{x-1}=\sqrt{2x-3}+\sqrt{4x-16}\)
7) \(\sqrt{x+2\sqrt{x-1}}+\sqrt{x-2\sqrt{x-1}}=\dfrac{x+3}{2}\)
Giúp mình với ajk, mink đang cần gấp
\(x-2\sqrt{x-1}-\left(x-1\right)\sqrt{x}+\sqrt{x^2-x}=0\)
Giải phương trình:
1. \(x\sqrt{x}+\dfrac{32}{x\sqrt{x}}=6\sqrt[3]{3x-4}\)
2. \(\sqrt{x^2+x-1}+\sqrt{-x^2+x+1}=x^2-x+2\)
3. \(\sqrt{8-x^2}+\sqrt{\dfrac{x^2-2}{2x^2}}=5-\dfrac{1+x^2}{x}\)
4. \(x^4-12x^3+38x^2-12x-67+\sqrt{x+1}+\sqrt{7-x}=0\)
1, \(x^3-x-3=2\sqrt{6x-x^2}\)
2, \(x^3+6x^2-171x-40\left(x+1\right)\sqrt{5x-1}+20=0\)
3, \(\sqrt[3]{x+3}+\sqrt[3]{x-3}=\sqrt[5]{x-5}+\sqrt[5]{x+5}\)
4. \(\left(\frac{1}{\sqrt{x}}-\frac{\sqrt{x}}{x+1}\right)^2=\frac{4\left(1+\sqrt{1+4x}\right)}{x+1+\sqrt{x^2+3x+2}}\)
Giải ft ( lập bảng xét dấu nếu cần )
1. \(\sqrt{5x-1}-\sqrt{3x-2}-\sqrt{x-1}=0\)
2. \(1+\frac{2}{3}\sqrt{x-x^2}=\sqrt{x}+\sqrt{1-x}\)
Cho A = \(\frac{x^2-\sqrt{x}}{x+\sqrt{x+1}}-\frac{x^2+\sqrt{x}}{x-\sqrt{x+1}}\)
Rút gọn B= 1-\(\sqrt{2}\sqrt{A+2x+\frac{1}{2}}\) với 0 \(\le\)x\(\le\)1/4
Giải phương trình:
a. \(4\sqrt{x+1}-1=3x+2\sqrt{1-x}+\sqrt{1-x^2}\)
b. \(\left(x+2\right)\left(\sqrt{2x+3}-2\sqrt{x+1}\right)+\sqrt{2x^2+5x+3}-1=0\)
Giải các phương trình sau:
a) \(\sqrt{x-1}+\sqrt{x-2}=\sqrt{x+1}\)
b) \(x^2+2x+3\sqrt{x^2+2x+2}-6=0\)
c) \(\sqrt{\left(x+1\right)\left(2-x\right)}-1+2x=2x^2\)
d) \(\sqrt{\frac{2x}{x+1}}+\sqrt{\frac{x+1}{2x}}=2\)
Giải hpt :
\(\left\{{}\begin{matrix}2\sqrt{x+3y+2}-3\sqrt{y}=\sqrt{x+2}\\\sqrt{y-1}-\sqrt{4-x}+8-x^2=0\end{matrix}\right.\)
