Question

Tìm x : | x - 2/3 | = 2

Answer 1

Với x >= 2/3 thì"

\(\left|x-\frac{2}{3}\right|=2\Leftrightarrow x-\frac{2}{3}=2\Leftrightarrow x=\frac{8}{3}\left(TM\right)\)

Với x < 2/3 thì:

\(\left|x-\frac{2}{3}\right|=2\Leftrightarrow\frac{2}{3}-x=2\Leftrightarrow x=-\frac{4}{3}\left(TM\right)\)

Vậy..

Answer 2

|x - \(\frac{2}{3}\)| = 2

Th1:

x - \(\frac{2}{3}\) = 2

=> x = \(\frac{8}{3}\)

Th2:

x - \(\frac{2}{3}\) = -2

=> x = - \(\frac{4}{3}\)

Answer 3

Tìm \(x\) :

\(\left|x-\frac{2}{3}\right|=2\)

\(\Rightarrow\left[{}\begin{matrix}x-\frac{2}{3}=2\\x-\frac{2}{3}=-2\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=2+\frac{2}{3}\\x=2+\frac{2}{3}\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=\frac{6}{3}+\frac{2}{3}=\frac{8}{3}\\x=\frac{-6}{3}+\frac{2}{3}=\frac{-4}{3}\end{matrix}\right.\)

Vậy \(x\)=\(\frac{8}{3}\) hoặc \(x=\frac{-4}{3}\)

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Answer 4

\(\Leftrightarrow\left[{}\begin{matrix}x-\frac{2}{3}=2\\x-\frac{2}{3}=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2+\frac{2}{3}\\x=-2+\frac{2}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\frac{8}{3}\\x=-\frac{4}{3}\end{matrix}\right.\)

Answer 5

| x - 2/3 | = 2

TH 1 : \(x-\frac{2}{3}=2\)

\(x=2+\frac{2}{3}\)

\(x=\frac{8}{3}\)

TH 2 : \(x-\frac{2}{3}=-2\)

\(x=-2+\frac{2}{3}\)

\(x=\frac{-4}{3}\)

Vậy x ∈ \(\left\{\frac{8}{3};\frac{-4}{3}\right\}\)

Answer 6

|x-\(\frac{2}{3}\)|=2

<=>\(\left[{}\begin{matrix}x-\frac{2}{3}=2\\x-\frac{2}{3}=-2\end{matrix}\right.\)

<=>\(\left[{}\begin{matrix}x=\frac{8}{3}\\x=\frac{-4}{3}\end{matrix}\right.\)