Để \(\dfrac{6x-5}{2x-1}\) có giá trị nguyên
<=> 6x - 5 \(⋮\) 2x - 1
<=> 6x - 3 - 2 \(⋮\) 2x-1
<=> 3(2x-1) - 2 \(⋮\) 2x-1
<=> 2 \(⋮\) 2x-1
<=> 2x-1 \(\in\) Ư(2) = {\(\pm1;\pm2\)}
<=> x \(\in\) {1;0;\(\dfrac{3}{2}\);\(-\dfrac{1}{2}\)}
😘Føllöw Ïţ Më😘