\(2.\left(x-1\right)^2-3=5\)
\(\Rightarrow2.\left(x-1\right)^2=8\)
\(\Rightarrow\left(x-1\right)^2=4\)
\(\Rightarrow x-1=\pm2\)
+) \(x-1=2\Rightarrow x=3\)
+) \(x-1=-2\Rightarrow x=-1\)
Vậy \(x\in\left\{3;-1\right\}\)
2 . (x - 1)2 - 3 = 5
2 . (x - 1)2 = 5+3
2 . (x - 1)2 = 8
(x - 1)2 = 8 : 2
(x - 1)2 = 4
x - 1 = 4 : 2
x - 1 = 2
x = 2 + 1
x = 3
2.(x-1)2 - 3 = 5
2.(x2-12) -3 = 5
2. (x-1) = 5+3
2. (x-1) = 8
x-1 =8 : 2
x2-1 = 4
x =4+1
x =5
Tui nghĩ z...
2. (x-1)2-3=5
=> 2.(x-1)2=5+3=8
=>(x-1)2=8:2=4
Mà: 22=4 hoặc (-2)2=4
=> x-1=2 hoặc x-1=-2
=> x=3 hoặc x= -1
Mà: x\(\in N\)=> x\(\ge0\)=>x=3