\(\sqrt{\frac{x^2-4}{x+1}}\) có nghĩa khi
\(\left\{{}\begin{matrix}x^2-4\ge0\\x+1\ne0\end{matrix}\right.\) => \(\left\{{}\begin{matrix}x-2\ge0\\x+2\ge0\\x+1\ne0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x\ge2\\x\ge-2\\x\ne-1\end{matrix}\right.\)