|5x-3|-x=7
=>|5x-3|=7+x
=>5x-3=-(7+x) hoặc 7+x
Nếu 5x-3=-(7+x)
=>5x-3=-x-7
=>6x=-4
=>x=\(-\frac{2}{3}\)
Nếu 5x-3=7+x
=>4x=10
=>x=\(\frac{5}{2}\)
I5x-3I-x=7
=> |5x-3|=7+x
=> TH1 :
5x-3=7+x
=> 5x-x=7+3
=> 4x = 10
=> x=2.5
TH2 :
5x-3=-(x+7)
=> 5x=-(x+7)+3
=> 5x=-x+((-7)+3)
=> 5x=-x+(-4)
=> 5x+x=-4
=> 6x=-4
=> x = -2/3
s mấy you k vào fx cho đẹp, dc tick nhìu
\(\left|5x-3\right|-x=7\)
\(\Rightarrow\left|5x-3\right|=7+x\)
\(\Rightarrow\left[\begin{array}{nghiempt}5x-3=7+x\\5x-3=-7-x\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}5x-x=7+3\\5x+x=-7+3\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}4x=10\\6x=-4\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=\frac{10}{4}\\x=-\frac{4}{6}\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=\frac{5}{2}\\x=-\frac{2}{3}\end{array}\right.\)
Vậy : \(x\in\left\{-\frac{2}{3};\frac{5}{2}\right\}\)
