\(\frac{3}{5}-\left[x-\frac{3}{4}.\left(2x-1\right)+2\right]=\frac{1}{2}\)
=> \(\left[x-\frac{3}{4}.\left(2x-1\right)+2\right]=\frac{3}{5}-\frac{1}{2}=\frac{1}{10}\)
=> \(x-\frac{3}{4}.\left(2x-1\right)+2=\frac{1}{10}\)
=> \(x-\frac{3}{4}.\left(2x-1\right)=\frac{1}{10}-2=\frac{-19}{10}\)
=> \(x-\frac{3}{2}x-\frac{3}{4}\) \(=\frac{-19}{10}\)
=> \(x-\frac{3}{2}x=\frac{-19}{10}+\frac{3}{4}=\frac{-23}{20}\)
=> \(\frac{3}{2}x=x-\frac{-23}{20}=\frac{43}{20}\)
=> \(x=\frac{43}{20}:\frac{3}{2}=\frac{43}{30}\)