X^2-2X+3=0
=> X^2+x-3x+3=0
=>x(x+1)-3(X+1)=0
<=>X-3=0 hoặc X+1=0
<=> x=3 hoặc x=-1
Tik nha!!
\(x^2-2x+3=0\)
\(\Leftrightarrow x^2-3x+x-3=0\)
\(\Leftrightarrow x\left(x-3\right)+\left(x-3\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(x-3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+1=0\\x-3=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=3\end{matrix}\right.\)
Vậy ...............
Ta có:
\(x^2-2x+3=0\)
\(\Leftrightarrow\left(x-1\right)^2+2=0\)
\(\Leftrightarrow\left(x-1\right)^2=-2\) (vô lí).
Vậy x \(\in\varnothing\).