\(\left|x-7\right|+2x+5=6\)
\(\Leftrightarrow\left|x-7\right|+2x=6-5\)
\(\Leftrightarrow\left|x-7\right|+2x=1\)
\(\Leftrightarrow\left[{}\begin{matrix}x-7+2x=1\left(đk:x-7\ge0\right)\\-\left(x-7\right)+2x=1\left(đk:x-7< 0\right)\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{8}{3}\left(đk:x\ge7\right)\\x=-6\left(đk:x< 7\right)\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x\in\varnothing\\x=-6\end{matrix}\right.\)
Vậy \(x=-6\)
Đúng 0
Bình luận (0)
