( x - 3 )2 -2 = \(\dfrac{14}{9}\)
( x - 3 )2 = \(\dfrac{14}{9}+2\)
( x - 3 )2 = \(\dfrac{32}{9}\)
( x - 3 )2 = \(\left(\dfrac{4\sqrt{2}}{3}\right)^2\)
⇒(x - 3)= ............
Ta có: (x-3)2 - 2 =\(\dfrac{14}{9}\)
Nên (x-3)2=\(\dfrac{14}{9}+2=\dfrac{32}{9}\)
Do đó: x-3= \(\sqrt{\dfrac{32}{9}}\) hoặc x-3= \(-\sqrt{\dfrac{32}{9}}\)
Suy ra: x= \(\sqrt{\dfrac{32}{9}}\)+3 hoặc x= \(-\sqrt{\dfrac{32}{9}}\)+3