Question

Tìm x biết rằng 

(2\(\frac{1}{9}\) - \(\frac{15}{2135}\) : \(\frac{9}{4270}\) ) : x = \(\frac{222}{333}\) : \(\frac{2121}{4040}\) : \(\frac{132132}{660660}\)

mọi người giúp vs

Answer 1

Ta có :

\(\frac{222}{333}=\frac{2}{3}\)

\(\frac{2121}{4040}=\frac{21}{40}\)

\(\frac{132132}{660660}=\frac{1}{5}\)

=> \(\frac{222}{333}:\frac{2121}{4040}:\frac{132132}{660660}=\frac{400}{63}\)

Thay vế phải vào ta được :

\(\left(2\frac{1}{9}-\frac{15}{2135}:\frac{9}{4270}\right):x=\frac{400}{63}\)

\(\Rightarrow\left(-\frac{11}{9}\right):x=\frac{400}{63}\)

\(\Rightarrow x=-\frac{11}{9}:\frac{400}{63}\)

\(\Rightarrow x=-\frac{77}{400}\)

Answer 2

Ta có:(2\(\dfrac{1}{9}\)-\(\dfrac{15}{2135}\) :\(\dfrac{9}{4270}\)): x= \(\dfrac{222}{333}\): \(\dfrac{2121}{4040}\): \(\dfrac{132132}{660660}\)

Suy ra (\(\dfrac{19}{9}\)-\(\dfrac{15}{2135}\) . \(\dfrac{4270}{9}\)): x= \(\dfrac{2}{3}\). \(\dfrac{40}{21}\) . 5

Suy ra (\(\dfrac{19}{9}\)-\(\dfrac{10}{3}\)): x=\(\dfrac{400}{63}\)

(\(\dfrac{-11}{9}\)):x =​\(\dfrac{400}{63}\)

Suy ra x= (\(\dfrac{-11}{9}\)):\(\dfrac{400}{63}\) Vậy x=\(\dfrac{-77}{400}\)