Đúng 0
Bình luận (0)
Ôn tập toán 7
Các câu hỏi tương tự
1. Tính hợp lí :
a) \(\frac{3}{4}-0,25-\left[\frac{7}{3}+\left(\frac{-9}{2}\right)\right]-\frac{5}{6}\)
b) 7 + \(\left(\frac{7}{12}-\frac{1}{2}+3\right)-\left(\frac{1}{12}+5\right)\)
2. Tìm các sô nguyên x biết:
\(\frac{3}{4}-\frac{5}{6}\le\frac{x}{12}< 1-\left(\frac{2}{3}-\frac{1}{4}\right)\)
Tìm x thỏa mãn:
a) \(2\left|\frac{2}{3}-x\right|+\frac{1}{4}=\frac{3}{4}\)
b) \(8\sqrt{x}+2x-9=5x+7+6\sqrt{x}-3x-12\)
c) \(2x^2+5x+8+\sqrt{x}=x^2+3x+35+x^2+2x-7\)
Tìm x biết :
a) \(-\frac{2}{3}.x+4=-12\)
b) \(-\frac{3}{4}+\frac{1}{4}:x=-3\)
c) \(\frac{x+1}{2}+\frac{x+2}{3}+\frac{x+1}{4}=\frac{x+1}{5}+\frac{x+1}{6}\)
d)\(\frac{x+1}{2009}+\frac{x+2}{2008}+\frac{x+3}{2007}=\frac{x+10}{2000}+\frac{x+11}{1999}+\frac{x+12}{1998}\)
Tìm số nguyễn x biết rằng: \(\frac{3}{7}.\frac{46}{3}+\frac{3}{7}.\frac{27}{5}\le x\le\left(\frac{7}{2}:7-\frac{13}{12}\right).\left(\frac{-7}{3}\right)\)
Giúp mk vs đg cần gấp nha cảm ơn mấy bạn nhiều lắm !!!left(frac{1}{2}right)^5.xleft(frac{1}{2}right)^7left(frac{3}{7}right)^2.xleft(frac{9}{21}right)^2Bài tìm x biết :2x23x347x77(-3)x(-3)5(-5)x(-5)42x42x82x163x+1325x-156x+461052x-7511(-2)4x+264left(frac{1}{2}right)^xleft(frac{1}{2}right)^5left(frac{5}{6}right)^{2x}left(frac{5}{6}right)^5left(frac{3}{4}right)^{2x-1}left(frac{3}{4}right)^{5x-4}left(-frac{1}{10}right)^xfrac{1}{100}left(-frac{3}{2}right)^xfrac{9}{4}left(-frac{3}{5}right)^{2x}frac{9}...
Đọc tiếp
Giúp mk vs đg cần gấp nha cảm ơn mấy bạn nhiều lắm !!!
\(\left(\frac{1}{2}\right)^5.x=\left(\frac{1}{2}\right)^7\)
\(\left(\frac{3}{7}\right)^2.x=\left(\frac{9}{21}\right)^2\)
Bài tìm x biết :
2x=2
3x=34
7x=77
(-3)x=(-3)5
(-5)x=(-5)4
2x=4
2x=8
2x=16
3x+1=32
5x-1=5
6x+4=610
52x-7=511
(-2)4x+2=64
\(\left(\frac{1}{2}\right)^x=\left(\frac{1}{2}\right)^5\)
\(\left(\frac{5}{6}\right)^{2x}=\left(\frac{5}{6}\right)^5\)
\(\left(\frac{3}{4}\right)^{2x-1}=\left(\frac{3}{4}\right)^{5x-4}\)
\(\left(-\frac{1}{10}\right)^x=\frac{1}{100}\)
\(\left(-\frac{3}{2}\right)^x=\frac{9}{4}\)
\(\left(-\frac{3}{5}\right)^{2x}=\frac{9}{25}\)
\(\left(-\frac{2}{3}\right)^x=-\frac{8}{27}\)
Tìm x in Za,frac{1}{2}-left(frac{1}{3}+frac{1}{4}right) x frac{1}{48}-left(frac{1}{16}-frac{1}{6}right)b, frac{3}{4}-frac{5}{6}lefrac{x}{12} 1-left(frac{2}{3}-frac{1}{3}right)c, x:left(frac{1}{2}right)^2frac{-1}{2}d,left(x^4right)^2frac{x^{12}}{x^5}left(xne0right)e,frac{3^2.3^8}{27^3}3^xf,2^{x-1}left(16right)^5
Đọc tiếp
Tìm x \(\in\) Z
a,\(\frac{1}{2}-\left(\frac{1}{3}+\frac{1}{4}\right)< x< \frac{1}{48}-\left(\frac{1}{16}-\frac{1}{6}\right)\)
b, \(\frac{3}{4}-\frac{5}{6}\le\frac{x}{12}< 1-\left(\frac{2}{3}-\frac{1}{3}\right)\)
c, \(x:\left(\frac{1}{2}\right)^2=\frac{-1}{2}\)
d,\(\left(x^4\right)^2=\frac{x^{12}}{x^5}\left(x\ne0\right)\)
e,\(\frac{3^2.3^8}{27^3}=3^x\)
f,\(2^{x-1}=\left(16\right)^5\)
a/ \(\frac{-15}{12}x+\frac{3}{7}=\frac{6}{5}x-\frac{1}{2}\)
b/\(\frac{12+x}{7}=\frac{x-4}{3}\)
x: (-5/14) \(+3\frac{1}{2}=-1\frac{2}{3}\)
\(3\frac{1}{4}x-\frac{7}{6}x=\frac{-5}{12}+1\frac{2}{3}\)
Tìm x \(\in\) Q:
a) \(\frac{11}{12}-\left(\frac{2}{5}+x\right)=\frac{2}{3}\)b) \(2x\left(x-\frac{1}{7}\right)=0\)c) \(\frac{3}{4}+\frac{1}{8}.x=\frac{2}{5}\)