tìm x
a,{[(3x+14):22-3]:2}-1=0
b,10-{[x:4+17):10+3.24] :10}=5
c,2.52.32+{[2.53-(2x+4).5]:(22+3.5)}=453
d,(19x+2.52):14=(13-8)2-42
e,2.3x=10.312+8.274
f,[3(x+2):7].4=120
g,2480-4710:3+[200-(x-5)]=1010
NHANH LÊN GIÚP TỚ VỚI MAI TỚ PHẢI NỘP RÙI XIN MỌI NGƯỜI ĐÓ
\(\text{Tìm x, biết:}\)
\(a\)) \(\left(19x+2.5^2\right):14=\left(13-8\right)^2-4^2\)
\(b\)) \(x+\left(x+1\right)+\left(x+2\right)+...+\left(x+30\right)=1240\)
\(c\)) \(11-\left(-53+x\right)=97\)
\(d\)) \(-\left(x+84\right)+213=-16\)
Bài 1: rút gọn các phân số sau:
a) \(\frac{3^{10}.\left(-5\right)^{21}}{\left(-5\right)^{20}.3^{12}}\)
b) \(\frac{-11^5.13^7}{11^5.13^8}\)
c) \(\frac{2^{10}.3^{10}-2^{10}.3^9}{2^9.3^{10}}\)
d) \(\frac{5^{11}.7^{12}+5^{11}.7^{11}}{5^{12}.7^{12}+9.5^{11}.7^{11}}\)
\(\text{Thực hiện các phép tính sau một cách hợp lý:}\)
\(a\)) \(\left(10^2+11^2+12^2\right):\left(13^2+14^2\right)\)
\(b\)) \(1.2.3...9-1.2.3...8-1.2.3...7.8^2\)
\(c\)) \(\dfrac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(d\)) \(1152-\left(374+1152\right)+\left(-65+374\right)\)
\(e\)) \(13-12+11+10-9+8-7-6+5-4+3+2-1\)
RÚT GỌN
\(a,\dfrac{121.75.130.169}{39.60.11.198}\)
\(b,\dfrac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}.16^9}\)
\(c,\dfrac{5.\left(2^2.3^2\right)^9.\left(2^2\right)^6-2.\left(2^2.3\right)^{14}.3^6}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)
TÍNH HỢP LÍ
\(a,\left(10^2+11^2+12^2\right):\left(13^2+14^2\right)\)
TÍNH NHANH
\(a,13-12+11+10-9+8-7-6+-4+3+2-1\)
\(\left(19X+2.5^2\right):14=\left(13-8\right)^2-4^2\)
Rút gọn biểu thức :
\(\frac{5^2.6^{11}.16^2+6^2.12^6.15^2}{2.6^{12}.10^4-81^2.960^3}\)
\(\frac{\left(5^2.6^{11}.16^2+6^2.12^6.15^2\right).10}{2.6^{12}.10^4-81^2.960^3}\)
Giải ra bn nhé !
Bài 1:
a)\(\frac{5}{6}\)-\(\frac{2}{3}+\frac{1}{4}\) b)\(1\frac{11}{12}-\frac{5}{12}\cdot\left(\frac{4}{5}-\frac{1}{10}\right):\frac{-5}{12}\)
Bài 2:
a) \(\frac{1}{2}\cdot x-\frac{2}{5}=\frac{1}{5}\) b)\(\left(1-2\cdot x\right)\cdot\frac{4}{3}=\left(-2\right)^3\)
tính bằng cách hợp lí
a) \(\left(10^2+11^2+12^2\right):\left(13^2+14^2\right)\)
b) \(1\cdot2\cdot3\cdot4\cdot...\cdot8\cdot9-1\cdot2\cdot3\cdot4\cdot...\cdot7\cdot8-1\cdot2\cdot3\cdot...\cdot7\cdot8^2\)
c) \(\frac{\left(3\cdot4\cdot2^{16}\right)^2}{11\cdot2^{13}\cdot4^{11}-16^9}\)
giúp em với ạ