x ( x + 2 ) = 2 ( x + 8 )
x2 + 2x = 2 ( x + 8 )
x2 + 2x = 2x + 16
x2 + 2x − 2x = 16
x2 = 16
x = 4
x = −4
x2+2x=2x+16
x2+16=0
x2=-16 (vô lí)
=> PT vô nghiệm
ĐK: x≠−2
x+2/2=8/x+2
⇔(x+2)2=8.2
⇔(x+2)2=42=(−4)2
⇔[x+2=4
x+2=−4
⇔[x=2x=−6
x+22=8x+2
Vậy x=2;x=−6x=2;x=−6.
x ( x + 2 ) = 2 ( x + 8 )
x2 + 2x = 2 ( x + 8 )
x2 + 2x = 2x + 16
x2 + 2x − 2x = 16
x2 = 16
x = 4
x = −4
x2+2x=2x+16
x2+16=0
x2=-16 (vô lí)
=> PT vô nghiệm
x ( x + 2 ) = 2 ( x + 8 )
x2 + 2x = 2 ( x + 8 )
x2 + 2x = 2x + 16
x2 + 2x − 2x = 16
x2 = 16
x = 4
x = −4