a) \(\dfrac{3x}{5}=\dfrac{1-4x}{3}\)
⇔ 9x = 5(1-4x)
⇔ 9x = 5 - 20x
⇔ 9x + 20x = 5
⇔ 29x = 5
⇔ x = \(\dfrac{5}{29}\)
b) \(\dfrac{x}{5}=\dfrac{15}{3x}\)
ĐKXĐ : x≠0
⇔ \(\dfrac{x}{5}=\dfrac{5}{x}\)
⇔ x2 = 25
⇔ x = 5 ; x = -5
a) \(\dfrac{3x}{5}=\dfrac{1-4x}{3}\)
⇔ 9x = 5(1-4x)
⇔ 9x = 5 - 20x
⇔ 9x + 20x = 5
⇔ 29x = 5
⇔ x = \(\dfrac{5}{29}\)
b) \(\dfrac{x}{5}=\dfrac{15}{3x}\)
ĐKXĐ : x≠0
⇔ \(\dfrac{x}{5}=\dfrac{5}{x}\)
⇔ x2 = 25
⇔ x = 5 ; x = -5
làm đầy đủ theo các bước nhé
Tìm x biết :
a) \(^{\dfrac{4}{9}+x=\dfrac{5}{3}}\)
b)\(\dfrac{3}{4}.x=\dfrac{-1}{2}\)
c) \(\dfrac{3}{7}+\dfrac{5}{7}:x=\dfrac{1}{3}\)
d)\(3\dfrac{1}{4}:\left|2x-\dfrac{5}{12}\right|=\dfrac{39}{16}\)
tìm x biết :
a) \(\left|x+\dfrac{1}{2}\right|\)=\(\dfrac{5}{2}\) b) \(\left|2x-\dfrac{2}{3}\right|\)+\(\dfrac{1}{3}\)=0 c) |x-2| = 2x + 1
Bài 1: Tìm x, biết
a) 3\(\dfrac{1}{3}\) x+ 16\(\dfrac{3}{4}\) = -13,25
b) 3\(\dfrac{2}{7}\).x - \(\dfrac{1}{8}\) = 2\(\dfrac{3}{4}\)
c) x : 4\(\dfrac{1}{3}\) = - 2,5
d) (\(\dfrac{3x}{7}\) + 1) : (-4) = \(\dfrac{-1}{28}\)
giúp em
\(\color{red}{\text{Tìm X }}\):
\(a) |x|=\)\(\dfrac{1}{5}\)\(+\)\(\dfrac{3}{4}\)
\(b)|x-5|=-\)\(\dfrac{5}{3}+\dfrac{1}{4}\)
\(\color{red}{\text{Giúp em với ak}}\)
câu 1 : tìm a,b ϵ Z biết : \(\dfrac{a}{3}=\dfrac{b}{2}=\dfrac{c}{5}\) và a - b + 2c = 77
câu 2 : (x\(^n\))\(^m\) = ?
Bài 1: Tìm x, biết
a)\(\dfrac{-2}{3}\)- \(\dfrac{1}{3}\) (2x-5) = \(\dfrac{3}{2}\)
b)\(\dfrac{2}{5}\) .x +\(\dfrac{1}{2}\) = \(\dfrac{-3}{4}\)
giúp em
Tìm giá trị của biểu thức :
\(A=-1,6:\left(1+\dfrac{2}{3}\right)\)
\(B=1,4.\dfrac{15}{49}-\left(\dfrac{4}{5}+\dfrac{2}{3}\right):2\dfrac{1}{5}\)
1. tìm các số nguyên x biết
a. \(\dfrac{1}{3}\)+\(\dfrac{3}{35}\)<\(\dfrac{x}{210}\)<\(\dfrac{4}{7}\)+\(\dfrac{3}{5}\)+\(\dfrac{1}{3}\)
b. \(\dfrac{5}{3}\)+\(\dfrac{-14}{3}\)<\(x\)<\(\dfrac{8}{5}\)+\(\dfrac{18}{10}\)
1) tính hợp lí ( nếu có thể )
c) \(\dfrac{2}{-11}\). 6\(\dfrac{2}{7}\)+ \(\dfrac{3}{7}\):3 + 5 d) 1,75 : 5 + 2,5 . ( \(4^2\)- 4. 4,1)
2) tìm x
a) 1/2-x=-1/6 b) x+3,5=7,8-12,6:2 c) 7/35 = 35-x/-105