Ta có:
2x(x - 5) - x(2x + 3) = 26
<=> 2x2 - 10x - 2x2 - 3x = 26
<=> -13x = 26
<=> x = 26 : (-13)
<=> x= -2
Vậy x= -2
\(2x\left(x-5\right)-x\left(2x+3\right)=26\)
\(\Leftrightarrow2x^2-10x-2x^2-3x=26\)
\(\Leftrightarrow-13x=26\Leftrightarrow x=-2\)
2x (x-5)-x (2x+3)=26
x(2 (x-5)-(2x+3))=26
x (2x-10-2x-3)=26
x (-13)=26
x=-2
2x( x - 5 ) - x( 2x + 3 ) = 26
\(\Leftrightarrow\) \(2x^2\) - \(10x\) - \(2x^2\) - \(3x\) = \(26\)
\(\Leftrightarrow\) \(-13x\) = \(26\)
\(\Rightarrow\) \(x=-2\)