1+2+3+...+x=55
\(\Rightarrow\frac{\left(n+1\right)n}{2}=55\)
=> (n + 1)n = 55 . 2
=> (n + 1)n = 110
=> (n + 1)n = 11.10
=> n = 10
1+2+3+...+x=55
\(\Rightarrow\frac{\left(x+1\right)x}{2}=55\)
=> (x + 1)x = 55.2
=> (x + 1)x = 110
Mà 110 = 11.10
=> x = 10