1, (2x+1)3 - (2x+1)(4x2-2x+1) - 3(2x-1)2 = 15
⇔ \(8x^3+12x^2+6x+1-8x^3-1-3\left(4x^2-4x+1\right)=15\)
⇔ \(12^2+6x-12x^2+12x-3=15\)
⇔ \(18x=18\)
⇔ x = 1
2, x(x-4)(x+4) - (x-5)(x2 +5x+25) = 13
⇔ \(x\left(x^2-16\right)-x^3+125=13\)
⇔ \(x^3-16x-x^3=-\text{112}\)
⇔ \(16x=112\)
⇔ x = 7