\(-5\left(x+\dfrac{1}{5}\right)-\dfrac{1}{2}\left(x-\dfrac{2}{3}\right)=\dfrac{3}{2}x-\dfrac{5}{6}\\ -5x+-5.\dfrac{1}{5}-\dfrac{1}{2}x-\dfrac{1}{2}.\dfrac{2}{3}=\dfrac{3}{2}x-\dfrac{5}{6}\\ -5x+\dfrac{-5}{5}-\dfrac{1}{2}x-\dfrac{2}{6}=\dfrac{3}{2}x-\dfrac{5}{6}\)
\(-5x+\left(-1\right)-\dfrac{1}{2}x-\dfrac{1}{3}=\dfrac{3}{2}x-\dfrac{5}{6}\\ -5x-1-\dfrac{1}{2}x-\dfrac{1}{3}=\dfrac{3}{2}x-\dfrac{5}{6}\\ x.\left(-5-\dfrac{1}{2}\right)-1-\dfrac{1}{3}=\dfrac{3}{2}x-\dfrac{5}{6}\\ x.\dfrac{-11}{2}-1-\dfrac{1}{3}=\dfrac{3}{2}x-\dfrac{5}{6}\\ x.\dfrac{-11}{2}-1=\dfrac{3}{2}x-\dfrac{5}{6}+\dfrac{1}{3}\\ x.\dfrac{-11}{2}-1=\dfrac{3}{2}x-\left(\dfrac{5}{6}-\dfrac{1}{3}\right)\\ x.\dfrac{-11}{2}-1=\dfrac{3}{2}x-\dfrac{1}{2}\\ x.\dfrac{-11}{2}=\dfrac{3}{2}x-\left(\dfrac{1}{2}-1\right)\\ x.\dfrac{-11}{2}=\dfrac{3}{2}x-\dfrac{-1}{2}\)
Mình bí rùi! Có chỗ nào sai bạn nhắc mk nhé
