(4x + 3)3.(\(\frac{3}{2}\)+ 2x)2 = 0
\(\Rightarrow\left[{}\begin{matrix}\left(4x+3\right)^3=0\\\left(\frac{3}{2}+2x\right)^2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}4x+3=0\\\frac{3}{2}+2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\frac{-3}{4}\\x=\frac{-3}{4}\end{matrix}\right.\)
Vậy x = \(\frac{-3}{4}\)