\(2^{x+2}-2^x=96\)
\(\Rightarrow2^x.4-2^x=96\)
\(\Rightarrow2^x\left(4-1\right)=96\)
\(\Rightarrow2^x=32\)
\(\Rightarrow x=5\)
Vậy x = 5
\(2^{x+2}-2^x=96\)
\(\Rightarrow2^x.4-2^x=96\)
\(\Rightarrow2^x\left(4-1\right)=96\)
\(\Rightarrow2^x.3=96\)
\(\Rightarrow2^x=32\)
\(\Rightarrow x=5\)