Question

Tìm x

( 2x - 1 ) : ( 2x + 3 ) = ( x - 5) : ( x + 1)

Answer 1

\(\frac{2x-1}{2x+3}=\frac{x-5}{x+1}\)

\(\Rightarrow\frac{2x-1}{2x+3}-\frac{x-5}{x+1}=0\)

\(\Rightarrow\frac{\left(2x-1\right)\left(x+1\right)}{\left(2x+3\right)\left(x+1\right)}-\frac{\left(2x+3\right)\left(x-5\right)}{\left(2x+3\right)\left(x+1\right)}=0\)

\(\Rightarrow\frac{2x^2+x-1-2x^2+7x+15}{\left(2x+3\right)\left(x+1\right)}=0\)

\(\Rightarrow\frac{8x+14}{\left(2x+3\right)\left(x+1\right)}=0\)

\(\Rightarrow8x+14=0\)

\(\Rightarrow8x=-14\)

\(\Rightarrow x=-\frac{7}{4}\)

Answer 2

cách đơn giản hơn thì nhân chéo