\(\Leftrightarrow2\cdot2\cdot\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+...+\dfrac{1}{x}-\dfrac{1}{x+1}\right)=\dfrac{2016}{2018}\)
\(\Leftrightarrow\dfrac{1}{4}-\dfrac{1}{x+1}=\dfrac{252}{1009}\)
\(\Leftrightarrow\dfrac{1}{x+1}=\dfrac{1}{4036}\)
=>x+1=4036
hay x=4035