a) \(\left(x-1\right)\left(y+2\right)=7\)
\(\Leftrightarrow\left(x-1\right)\left(y+2\right)=1.7=7.1=\left(-1\right).\left(-7\right)=\left(-7\right).\left(-1\right)\)
Ta có bảng sau:
| \(x-1\) | \(1\) | \(7\) | \(-1\) | \(-7\) |
| \(y+2\) | \(7\) | \(1\) | \(-7\) | \(-1\) |
| \(x\) | \(2\) | \(8\) | \(0\) | \(-6\) |
| \(y\) | \(5\) | \(-1\) | \(-9\) | \(-3\) |
Vậy \(\left\{{}\begin{matrix}x=2\\y=5\end{matrix}\right.\left\{{}\begin{matrix}x=8\\y=-1\end{matrix}\right.\left\{{}\begin{matrix}x=0\\y=-9\end{matrix}\right.\left\{{}\begin{matrix}x=-6\\y=-3\end{matrix}\right.\)
b) \(\left(x-2\right)\left(2y+1\right)=17\)
\(\Rightarrow\left(x-2\right)\left(2y+1\right)=1.17=17.1=\left(-1\right).\left(-17\right)=\left(-17\right).\left(-1\right)\)
Ta có bảng sau:
| \(x-2\) | \(1\) | \(17\) | \(-1\) | \(-17\) |
| \(2y+1\) | \(17\) | \(1\) | \(-17\) | \(-1\) |
| \(x\) | \(3\) | \(19\) | \(1\) | \(-15\) |
| \(y\) | \(8\) | \(0\) | \(-9\) | \(-1\) |
Vậy \(\left\{{}\begin{matrix}x=3\\y=8\end{matrix}\right.\left\{{}\begin{matrix}x=19\\y=0\end{matrix}\right.\left\{{}\begin{matrix}x=1\\y=-9\end{matrix}\right.\left\{{}\begin{matrix}x=-15\\y=-1\end{matrix}\right.\)
