\(x^2-3x-xy+3y=7\)
\(=>\left(x^2-xy\right)-\left(3x-3y\right)=7\)
\(=>x.\left(x-y\right)-3.\left(x-y\right)=7\)
\(=>\left(x-3\right).\left(x-y\right)=7\)
Ta co bảng
\(x-3\) | - 7 | - 1 | 1 | 7 |
\(x\) | - 4 | 2 | 4 | 10 |
\(x-y\) | - 1 | - 7 | 7 | 1 |
\(y\) | - 3 | 9 | - 3 | 9 |