\(-x^2+3\)
Ta có:
\(-x^2+3=0\)
\(\Rightarrow-x^2=-3\Rightarrow x^2=3\)
\(\Rightarrow x=\pm\sqrt{3}\)
Vậy nghiệm của đa thức là \(\pm\sqrt{3}\).
Chúc bạn học tốt!!!
Mk nghĩ thế này.
Ta có: \(-x^2+3=0\)
\(\Rightarrow-\left(x^2\right)=0-3=-3\)
\(\Rightarrow x^2=3\)
\(\Rightarrow\left[{}\begin{matrix}x=\sqrt{3}\\x=-\sqrt{3}\end{matrix}\right.\)
Vậy \(\left[{}\begin{matrix}x=\sqrt{3}\\x=-\sqrt{3}\end{matrix}\right.\).
\(-x^2+3=0\Leftrightarrow-x^2=-3\Leftrightarrow x^2=3\Leftrightarrow x=\sqrt{3};x=-\sqrt{3}\)
Vậy ...
Ta có: \(-x^2+3=0\)
\(\Rightarrow-x^2=-3\)
\(\Leftrightarrow x^2=3\)
\(\Leftrightarrow\left[{}\begin{matrix}x^2=3\\x^2=-3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\sqrt{3}\\x=-\sqrt{3}\end{matrix}\right.\)
Vậy \(x_1=-\sqrt{3};x_2=\sqrt{3}\)
\(-x^2+3=0\)
\(-x^2=0-3\)
\(-x^2=-3\)
\(\Leftrightarrow x^2=3\)
\(\Leftrightarrow x=\sqrt{3}\)
\(\Leftrightarrow x=\sqrt{-3}\)
