Đặt A(x)=0
\(\Leftrightarrow2x^2+7x=0\)
\(\Leftrightarrow x\left(2x+7\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\2x+7=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\2x=-7\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\frac{-7}{2}\end{matrix}\right.\)
Vậy: \(S_{A_{\left(x\right)}}=\left\{0;\frac{-7}{2}\right\}\)
Đặt B(x)=0
\(\Leftrightarrow x^2-x=0\)
\(\Leftrightarrow x\left(x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)
Vậy: \(S_{B_{\left(x\right)}}=\left\{0;1\right\}\)