a) \(\left(\dfrac{1}{2}\right)^n=\dfrac{1}{32}\)
\(\Rightarrow\left(\dfrac{1}{2}\right)^n=\dfrac{1^5}{2^5}\)
\(\Rightarrow n=5\)
Vậy n = 5
c) \(\dfrac{1}{9}\cdot27=3^n\)
\(\Rightarrow3=3^n\)
\(\Rightarrow n=1\)
Vậy n = 1
d) \(3^{-2}\cdot3^4\cdot3^n=3^7\)
\(\Rightarrow3^2\cdot3^n=3^7\)
\(\Rightarrow3^n=3^5\)
\(\Rightarrow n=5\)
Vậy n = 5