x1^2+x2^2=(x1+x2)^2-2x1x2
=m^2-2(m-1)=m^2-2m+2
=>x1^2=m^2-2m+2-x2^2
x1^2+3x2=19
=>m^2-2m+2-x2^2+3x2=19
=>-x2^2+3x2+m^2-2m-17=0
=>x2^2-3x2-m^2+2m+17=0(1)
Để (1) có nghiệm thì Δ1>0
=>(-3)^2-4*1*(-m^2+2m+17)>0
=>9-4(-m^2+2m+17)>0
=>9+4m^2-8m-68>0
=>4m^2-8m-59>0
=>\(\left[{}\begin{matrix}m< \dfrac{2-3\sqrt{7}}{2}\\m>\dfrac{2+3\sqrt{7}}{2}\end{matrix}\right.\)