dễ thấy \(\Delta=m^2-2m+1=\left(m-1\right)^2\ge0\)
\(x_1=\dfrac{3m-1+\left|m-1\right|}{2}\) ;\(x_2=\dfrac{3m-1-\left|m-1\right|}{2}\)
xét m\(\ge1\)
\(\Rightarrow x_1=2m-1;x_2=m\)
\(x_1=x_2^2\Rightarrow m=1\left(tm\right)\)
xét m\(\le1\)
\(\Rightarrow x_2=2m-1;x_1=m\)
\(x_1=x_2^2\Rightarrow\left[{}\begin{matrix}m=1\\m=\dfrac{1}{4}\end{matrix}\right.\)