a: \(A=-4x^2+10x-23\)
\(=-4\left(x^2-\dfrac{5}{2}x+\dfrac{23}{4}\right)\)
\(=-4\left(x^2-2\cdot x\cdot\dfrac{5}{4}+\dfrac{25}{16}+\dfrac{67}{16}\right)\)
\(=-4\left(x-\dfrac{5}{4}\right)^2-\dfrac{67}{4}< =-\dfrac{67}{4}\)
Dấu '=' xảy ra khi x=5/4
b: \(x^2-2x+3=\left(x-1\right)^2+2>=2\)
=>B<=1/2
Dấu '=' xảy ra khi x=1