A=(x+1)(y2 - 6) = 0
Ta có:
\(\left[{}\begin{matrix}\left(x+1\right)=0\\\left(y^2-6\right)=0\end{matrix}\right.\left[{}\begin{matrix}x=\left(-1\right)\\y^2=6\Rightarrow y=\sqrt{6}\end{matrix}\right.\)
Vậy x = (-1) ; y = \(\sqrt{6}\)
- Coi vậy đúng chưa nhé bạn!