Ta có: \(\frac{-x}{6}=\frac{14}{y}=\frac{x}{60}=\frac{2}{3}\)
\(\Leftrightarrow\left\{{}\begin{matrix}\frac{-x}{6}=\frac{2}{3}\\\frac{14}{y}=\frac{2}{3}\\\frac{z}{60}=\frac{2}{3}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}-x=\frac{2\cdot6}{3}\\y=\frac{14\cdot3}{2}\\z=\frac{2\cdot60}{3}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-4\\y=21\\z=40\end{matrix}\right.\)
Vậy: x=-4; y=21 và z=40