\(\dfrac{3}{11}+\dfrac{a}{22}=\dfrac{b}{11}\Rightarrow\dfrac{6}{22}+\dfrac{a}{22}=\dfrac{2b}{22}\\ \Rightarrow6+a=2b\)
a và b nguyên khi a là số chẵn.
1 tinh
a,\(5\dfrac{4}{23}.27\dfrac{3}{47}+4\dfrac{3}{47}.\left(-5\dfrac{4}{23}\right)\)
b,4.\(\left(\dfrac{-1}{2}\right)^3+\dfrac{3}{2}\)
c,\(\left(\dfrac{1999}{2011}-\dfrac{2011}{1999}\right)-\left(\dfrac{-12}{1999}-\dfrac{12}{2011}\right)\)
d,\(\left(\dfrac{-5}{11}+\dfrac{7}{22}-\dfrac{-4}{33}-\dfrac{5}{44}\right):\left(\dfrac{381}{22}-39\dfrac{7}{22}\right)\)
\(a,-\dfrac{2}{3}.\left(x-\dfrac{1}{4}\right)=\dfrac{1}{3}.\left(2x-1\right)\)
\(b,\dfrac{1}{5}.2^x+\dfrac{1}{3}.2^{x+11}=\dfrac{1}{5}.2^7+\dfrac{1}{3}.2^8\)
\(c,\dfrac{x-19}{345}+\dfrac{x-20}{346}=\dfrac{x-1}{347}+\dfrac{x-22}{348}\)
\(A=\dfrac{6}{19}.\dfrac{-7}{11}+\dfrac{6}{19}.\dfrac{-4}{11}+\dfrac{-13}{19}\)
\(B=\dfrac{5}{7}.\dfrac{-4}{13}+\dfrac{5}{7}.\dfrac{7}{3}-\dfrac{5}{13}.\dfrac{3}{7}\)
Bài 1: Thực hiện phép tính:
a, \(\left(\dfrac{7}{20}+\dfrac{11}{15}-\dfrac{15}{12}\right):\left(\dfrac{11}{20}-\dfrac{26}{45}\right)\)
b, \(\dfrac{5-\dfrac{5}{3}+\dfrac{5}{9}-\dfrac{5}{27}}{8-\dfrac{8}{3}+\dfrac{8}{9}-\dfrac{8}{27}}:\dfrac{15-\dfrac{15}{11}+\dfrac{15}{121}}{16-\dfrac{16}{11}+\dfrac{16}{121}}\)
c, \(\dfrac{\dfrac{1}{9}-\dfrac{5}{6}-4}{\dfrac{7}{12}-\dfrac{1}{36}-10}\)
A= \(\dfrac{6}{19}.\dfrac{-7}{11}+\dfrac{6}{19}.\dfrac{-4}{11}+\dfrac{-13}{19}\); B=\(\dfrac{5}{7}.\dfrac{-4}{13}+\dfrac{5}{7}.\dfrac{7}{13}-\dfrac{5}{13}.\dfrac{3}{7}\)
*Phép chia
a)\(11\dfrac{1}{4}-\left(2\dfrac{5}{7}+5\dfrac{1}{4}\right)\)
b)\(\left(8\dfrac{5}{11}+3\dfrac{5}{8}\right)-3\dfrac{5}{11}\)
c)\(\dfrac{-1}{4}.13\dfrac{9}{11}-0,25.6\dfrac{2}{11}\)
d)\(\dfrac{4}{9}:\left(\dfrac{-1}{7}\right)+6\dfrac{5}{9}:\left(\dfrac{-1}{7}\right)\)
Tính :
a) \(\dfrac{-2}{5}+25\%\) b) \(\dfrac{-2}{3}.\dfrac{8}{11}+\dfrac{-2}{3}.\dfrac{3}{11}\) c) \(\dfrac{-3}{4}.\dfrac{7}{8}+1\dfrac{1}{2}+\dfrac{-3}{4}:\dfrac{8}{9}\)
Tính hợp lí
a)\(11.\dfrac{1}{4}-\left(2\dfrac{5}{7}+5\dfrac{1}{4}\right)\)
b)\(\left(8\dfrac{5}{11}+3\dfrac{5}{8}\right)-3\dfrac{5}{11}\)
c)\(-\dfrac{1}{4}.13\dfrac{9}{11}-0,25.6\dfrac{2}{11}\)
d)\(\dfrac{4}{9}:\left(-\dfrac{1}{7}\right)+6\dfrac{5}{9}:\left(-\dfrac{1}{7}\right)\)
áp dụng tính chất phép tính và quy tắc phép tính và quy tắc dấu ngoặc để tính
\(A=11\dfrac{3}{13}-\left(3\dfrac{4}{7}+6\dfrac{3}{13}\right)=\)
\(B=\left(7\dfrac{4}{9}+3\dfrac{8}{13}\right)-5\dfrac{4}{9}\)=
\(C=\dfrac{-2}{7}.\dfrac{5}{11}+\dfrac{-2}{7}\dfrac{6}{11}+5\dfrac{4}{7}\)=
\(D=0,7.1\dfrac{3}{5}.30.0,375.\dfrac{4}{7}\)
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