Ta có :
\(a+b+c+d=66\)
\(a:b:c:d=7:6:5:4\)
\(\Leftrightarrow\dfrac{a}{7}=\dfrac{b}{6}=\dfrac{c}{5}=\dfrac{d}{4}\)
Áp dụng t/c dãy tỉ số bằng nhau ta có :
\(\dfrac{a}{7}=\dfrac{b}{6}=\dfrac{c}{5}=\dfrac{d}{4}=\dfrac{a+b+c+d}{7+6+5+4}=\dfrac{66}{22}=3\)
\(\Leftrightarrow\left\{{}\begin{matrix}\dfrac{a}{7}=3\Leftrightarrow a=21\\\dfrac{b}{6}=3\Leftrightarrow b=18\\\dfrac{c}{5}=3\Leftrightarrow c=15\\\dfrac{d}{4}=3\Leftrightarrow d=12\end{matrix}\right.\)
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