\(cd+acd+abcd=2005=>d=5\)
Ta có : \(c5+ac5+abc5=2005=>10c+5+100a+10c+5+1000a+100b+10c+5\)=2005
\(1100a+100b+30c+15=2005\\ \)
=>\(1100a+100b+30c=1990\)
=>a=1
=>1100+100b+30c=1990
=>100b+30c=890
=>b=8 ; c=3
Số cần tìm là : 1835
a=1;b=8;c=3;d=5
d=5,c=3,b=8,a=1
35+135+1835=2005
ủng hộ mình nha