ta có:
\(-3xy+4y-6x-27=0\)
\(\Rightarrow-3xy+4y-\left(6x+8\right)=19\)
\(\Rightarrow y\left(4-3x\right)-2\left(4-3x\right)=19\)
\(\Rightarrow\left(y-2\right)\left(4-3x\right)=19\)\(x,y\in Z\Rightarrow y-2,4-3x\inƯ\left(19\right)\)
ta có bảng:
\(\begin{matrix}y-2&1&-1&19&-19\\y&3&1&21&-17\\4-3x&19&-19&1&-1\\x&-5&\notin Z&1&\notin Z\end{matrix}\)
vậy...