a) \\(\\dfrac{44.52.60}{11.13.15}=\\dfrac{4.11.4.13.4.15}{11.13.15}=4^3=64\\)
b) \\(\\dfrac{168.168-168.58}{110}=\\dfrac{168\\left(168-58\\right)}{110}=168\\)
c) Đặt \\(A=2+4+6+...+18\\)
\\(A=\\dfrac{\\left(2+18\\right).\\left(\\dfrac{18-2}{2}+1\\right)}{2}=\\dfrac{20.9}{2}=90\\)
=> Ta có: \\(\\dfrac{27.45-27.55}{2+4+6+...+18}=\\dfrac{27.\\left(-10\\right)}{90}=-3\\)