Question

thực hiện phép tính

\(\dfrac{-5}{7}+\dfrac{3}{4}+\dfrac{-1}{5}+\dfrac{-2}{7}+\dfrac{1}{4}\)

giúp mình nhé

Answer 1

\(\dfrac{-5}{7}+\dfrac{3}{4}+\dfrac{-1}{5}+\dfrac{-2}{7}+\dfrac{1}{4}\)

\(=\left(\dfrac{-5}{7}+\dfrac{-2}{7}\right)+\left(\dfrac{3}{4}+\dfrac{1}{4}\right)+\dfrac{-1}{5}\)

\(=\left(-1\right)+1+\dfrac{-1}{5}\)

\(=0+\dfrac{-1}{5}\)

\(=\dfrac{-1}{5}\)

Answer 2

\(\dfrac{-5}{7}+\dfrac{3}{4}+\dfrac{-1}{5}+\dfrac{-2}{7}+\dfrac{1}{4}\)

=\(\left(\dfrac{-5}{7}+\dfrac{-2}{7}\right)+\left(\dfrac{3}{4}+\dfrac{1}{4}\right)+\dfrac{-1}{5}\)

=\(\left(-1\right)+1+\dfrac{-1}{5}\)

=\(0+\dfrac{-1}{5}=\dfrac{-1}{5}\)

Answer 3

\(\dfrac{-5}{7}+\dfrac{3}{4}+\dfrac{-1}{5}+\dfrac{-2}{7}+\dfrac{1}{4}\)

=\(\left(\dfrac{-5}{7}+\dfrac{-2}{7}\right)+\left(\dfrac{3}{4}+\dfrac{1}{4}\right)+\dfrac{-1}{5}\)

= \(\left(-1\right)+1+\dfrac{-1}{5}\)

= \(\dfrac{-1}{5}\)