ĐKXĐ: \(x\ge1\)
\(A=\sqrt{x+2\sqrt{x-1}}-\sqrt{x-2\sqrt{x-1}}\)
= \(\sqrt{\left(x-1\right)+2\sqrt{x-1}+1}-\sqrt{\left(x-1\right)-2\sqrt{x-1}+1}\)
= \(\sqrt{\left(\sqrt{x-1}+1\right)^2}-\sqrt{\left(\sqrt{x-1}-1\right)^2}\)
= \(\sqrt{x-1}+1-\sqrt{x-1}+1\) ( vì \(x\ge1\) )
= 2