a, (\(\frac{9}{25}\) - 2.18) : (\(3\frac{4}{5}\) + 0,2)
= (\(\frac{9}{25}\) - 36) : 4
= \(\frac{-891}{25}\) :4
= -8,91
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a) (925−2.18):(345+0,2)
= (\(\frac{9}{25}\) - 36) : (\(\frac{19}{5}\) + 0,2)
= \(\frac{-891}{25}\) : 4
= \(\frac{-891}{100}\)
b) 518−1,456:725+4,5.45
= \(\frac{5}{18}\) - (1,456 : \(\frac{7}{25}\)) + (4,5 . \(\frac{4}{5}\))
= \(\frac{5}{18}\) - \(\frac{26}{5}\) + \(\frac{18}{5}\)
= \(\frac{-443}{90}\) + \(\frac{18}{5}\)
= \(\frac{-119}{90}\).
a) \(\left(\frac{9}{25}-2.18\right):\left(3\frac{4}{5}+0,2\right)\)
\(=\left(\frac{9}{25}-36\right):\left(\frac{19}{5}+0,2\right)\)
\(=\left(-\frac{891}{25}\right):4\)
\(=-\frac{891}{100}\)
b)\(\frac{5}{18}-1,456:\frac{7}{25}+4,5.\frac{4}{5}\)
\(=\frac{5}{18}-\frac{26}{5}+\frac{18}{5}\)
\(=-\frac{119}{90}\)
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