Ta có: \(\sqrt{\left(11-6\sqrt{2}\right)^2}\)
\(=\left|11-6\sqrt{2}\right|\)
\(=11-6\sqrt{2}\)
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Bài 1: Căn bậc hai
Các câu hỏi tương tự
\(\left(\sqrt{11-6\sqrt{2}}\right)+\left(\sqrt{11+6\sqrt{2}}\right)\) giải theo 2 cách
Chứng minh rằng:
a)\(\frac{\left(5+2\sqrt{6}\right)\left(49-20\sqrt{6}\right)\left(\sqrt{5-2\sqrt{6}}\right)}{9\sqrt{3}-11\sqrt{2}}\) là số nguyên
b)\(\left(\sqrt{3}-1\right).\sqrt{6+2\sqrt{2}\sqrt{3-\sqrt{\sqrt{2}+\sqrt{12}+\sqrt{18-\sqrt{128}}}}}\)
Tính:
a)dfrac{-3}{5} . sqrt{left(-0,5right)^{ }2}
b)4.sqrt{left(-3right)^6} + 5sqrt{left(-2right)^4}
c)sqrt{left(1-sqrt{7}right)^2} +sqrt{7}
d)sqrt{11+6sqrt{2}} - sqrt{11-6sqrt{2}}
-GIÚP MÌNH VỚI Ạ-
Đọc tiếp
Tính:
a)\(\dfrac{-3}{5}\) . \(\sqrt{\left(-0,5\right)^{ }2}\)
b)4.\(\sqrt{\left(-3\right)^6}\) + 5\(\sqrt{\left(-2\right)^4}\)
c)\(\sqrt{\left(1-\sqrt{7}\right)^2}\) +\(\sqrt{7}\)
d)\(\sqrt{11+6\sqrt{2}}\) - \(\sqrt{11-6\sqrt{2}}\)
-GIÚP MÌNH VỚI Ạ-
Mn giúp mình vs.. mình đang cần gấp ạ, cảm ơn mn nhiều lắm.. hjx
sqrt{46-6sqrt{ }5}-sqrt{29-12sqrt{ }5}
sqrt{7-3sqrt{ }5}
left(3-sqrt{ }2right)sqrt{11+6sqrt{ }2}
sqrt{4+sqrt{ }15}
left(sqrt{ }5+sqrt{ }7right)sqrt{12-2sqrt{ }35}
sqrt{17-12sqrt[]{}2}
sqrt{14-6sqrt{ }5}
sqrt{27-12sqrt{ }5}
Đọc tiếp
\(\)Mn giúp mình vs.. mình đang cần gấp ạ, cảm ơn mn nhiều lắm.. hjx
\(\sqrt{46-6\sqrt{ }5}-\sqrt{29-12\sqrt{ }5}\)
\(\sqrt{7-3\sqrt{ }5}\)
\(\left(3-\sqrt{ }2\right)\sqrt{11+6\sqrt{ }2}\)
\(\sqrt{4+\sqrt{ }15}\)
\(\left(\sqrt{ }5+\sqrt{ }7\right)\sqrt{12-2\sqrt{ }35}\)
\(\sqrt{17-12\sqrt[]{}2}\)
\(\sqrt{14-6\sqrt{ }5}\)
\(\sqrt{27-12\sqrt{ }5}\)
\(\sqrt{\left(\sqrt{2}-3\right)^2}.\sqrt{11+6\sqrt{2}}\)
Rút gọn căn bậc hai theo hằng đẳng thức:
a)left(4sqrt{2}+sqrt{30}right).left(sqrt{5}-sqrt{3}right)sqrt{4-sqrt{15}}
b)2.left(sqrt{10}-sqrt{2}right).left(4+sqrt{6-2sqrt{5}}right)
c)left(7+sqrt{14}right).sqrt{9-2sqrt{14}}
d)sqrt{dfrac{289+4sqrt{72}}{16}}
e) left(sqrt{21}+7right).sqrt{10-2sqrt{21}}
f)sqrt{2-sqrt{3}.left(sqrt{6}+sqrt{2}right)}
g) sqrt{2}sqrt{8+3sqrt{7}}
h) sqrt{11+6sqrt{2}}
Đọc tiếp
Rút gọn căn bậc hai theo hằng đẳng thức:
a)\(\left(4\sqrt{2}+\sqrt{30}\right).\left(\sqrt{5}-\sqrt{3}\right)\sqrt{4-\sqrt{15}}\)
b)\(2.\left(\sqrt{10}-\sqrt{2}\right).\left(4+\sqrt{6-2\sqrt{5}}\right)\)
c)\(\left(7+\sqrt{14}\right).\sqrt{9-2\sqrt{14}}\)
d)\(\sqrt{\dfrac{289+4\sqrt{72}}{16}}\)
e) \(\left(\sqrt{21}+7\right).\sqrt{10-2\sqrt{21}}\)
f)\(\sqrt{2-\sqrt{3}.\left(\sqrt{6}+\sqrt{2}\right)}\)
g) \(\sqrt{2}\sqrt{8+3\sqrt{7}}\)
h) \(\sqrt{11+6\sqrt{2}}\)
1.Tính :
a.\(\sqrt{11+6\sqrt{2}}+\sqrt{19+6\sqrt{2}}\)
b.\(-\sqrt{2\left(2-\sqrt{3}\right)}+\sqrt{2\left(2+\sqrt{3}\right)}\)
c.\(\frac{\sqrt{7+4\sqrt{3}}+\sqrt{7-4\sqrt{3}}}{2\sqrt{3}}\)
1.Tính:
a.\(\sqrt{11+6\sqrt{2}-\sqrt{19+6\sqrt{2}}}\)
b.\(-\sqrt{2\left(2-\sqrt{3}\right)}+\sqrt{2\left(2+\sqrt{3}\right)}\)
c.\(\frac{\sqrt{7+4\sqrt{3}}+\sqrt{7-4\sqrt{3}}}{2\sqrt{3}}\)
\(\sqrt{7-\sqrt{24}}-\dfrac{\sqrt{50}-5}{\sqrt{10}-\sqrt{5}}+\sqrt{\left(11-\sqrt{120}\right)\left(11+2\sqrt{30}\right)^2}\)
Rút gọn giùm mình với ạ