\(A=\sqrt{4-\sqrt{10-2\sqrt{5}}}-\sqrt{4+\sqrt{10-2\sqrt{5}}}\)
\(A^2=4-\sqrt{10-2\sqrt{5}}+4+\sqrt{10-2\sqrt{5}}-2\sqrt{16-10+2\sqrt{5}}\)
\(A^2=8-2\sqrt{5+2\sqrt{5}+1}\)
\(A^2=8-2\left(\sqrt{5}+1\right)\)
\(A^2=5-2\sqrt{5}+1\)
\(A=\sqrt{5}-1\)
\(A=\sqrt{4-\sqrt{10-2\sqrt{5}}}-\sqrt{4+\sqrt{10-2\sqrt{5}}}\)
\(A^2=4-\sqrt{10-2\sqrt{5}}+4+\sqrt{10-2\sqrt{5}}-2\sqrt{16-10+2\sqrt{5}}\)
\(A^2=8-2\sqrt{5+2\sqrt{5}+1}\)
\(A^2=8-2\left(\sqrt{5}+1\right)\)
\(A^2=5-2\sqrt{5}+1\)
\(A=\sqrt{5}-1\)
thực hiện phép tính
A=\(\sqrt{4+\sqrt{10+2\sqrt{5}}}+\sqrt{4-\sqrt{10+2\sqrt{5}}}\)
B=\(\left(5+2\sqrt{6}\right)\cdot\left(49-20\sqrt{6}\right)\sqrt{5-2\sqrt{6}}\)
\(\sqrt{4+\sqrt{10+2\sqrt{5}}}+\sqrt{4-\sqrt{10+2\sqrt{5}}}\)
B=\(\sqrt{4+\sqrt{10+2\sqrt{5}}}+\sqrt{4-\sqrt{10+2\sqrt{5}}}\)
Rút gọn \(H=\sqrt{4+\sqrt{10+2\sqrt{5}}}+\sqrt{4-\sqrt{10+2\sqrt{5}}}\)
\(\sqrt{4+\sqrt{10+2\sqrt{5}}}+\sqrt{4-\sqrt{10-2\sqrt{5}}}\)
bạn nào làm giúp mk câu này với ạ
xin cảm ơn
Tính
a/ \(2\sqrt{\dfrac{9-\sqrt{77}}{2}}-\sqrt{\dfrac{2}{10-3\sqrt{11}}}\)
b/ \(\left(\sqrt{13}-1\right)\sqrt{\dfrac{2}{7-\sqrt{13}}}+\sqrt{4+\sqrt{10+2\sqrt{5}}}+\sqrt{4-\sqrt{10+2\sqrt{5}}}\)
So sánh:
a, 5+\(\sqrt{ }\)2 và 4+ \(\sqrt{ }\)3
b, \(\)\(\sqrt{ }\)8 - \(\sqrt{ }\)2 và \(\sqrt{ }\)5 - \(\sqrt{ }\)3
c, \(\sqrt{ }\)5 - \(\sqrt{ }\)3 và \(\sqrt{ }\)10 - \(\sqrt{ }\)7
thực hiện phép tính
\(\sqrt{4+\sqrt{10+2\sqrt{5}}}+\sqrt{4-\sqrt{10-2\sqrt{5}}}\)
Bài 1:
1.\(\sqrt{2-\sqrt{3}}\)
2.\(\sqrt{3+\sqrt{5}}\)
3.\(\sqrt{21-6\sqrt{6}}\)
4.\(\sqrt{5+2\sqrt{6}}-\sqrt{5-2\sqrt{6}}\)
5.\(\left(2-\sqrt{3}\right)\sqrt{7+4\sqrt{3}}\)
6.\(\sqrt{13+4\sqrt{10}}+\sqrt{13-4\sqrt{10}}\)