\(\sqrt{3x+1}=x-1\)ĐK : \(x\ge1\)
\(\Leftrightarrow3x+1=\left(x-1\right)^2\)
\(\Leftrightarrow x^2-2x+1-3x-1=0\)
\(\Leftrightarrow x^2-5x=0\)
\(\Leftrightarrow x\left(x-5\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\left(l\right)\\x=5\left(c\right)\end{matrix}\right.\)
\(\sqrt{4x^2-20x+25}=1\)
\(\Leftrightarrow\sqrt{\left(2x-5\right)^2}=1\)
\(\Leftrightarrow\left|2x-5\right|=1\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-5=1\\2x-5=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=2\end{matrix}\right.\)
Đúng 0
Bình luận (0)
