\(\sqrt[3]{\dfrac{3}{4}}.\sqrt[3]{\dfrac{9}{16}}=\sqrt[3]{\dfrac{3.9}{4.16}}=\sqrt[3]{\dfrac{27}{64}}=\dfrac{3}{4}\)
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Bài 9: Căn bậc ba
Các câu hỏi tương tự
Tính:
a)\(\sqrt[3]{125}.\sqrt[3]{\dfrac{16}{10}}.\sqrt[3]{-0,5}\)
b) \(\dfrac{\sqrt[3]{4}+\sqrt[3]{2}+2}{\sqrt[3]{4}+\sqrt[3]{2}+1}\)
c) \(\sqrt{3}+\sqrt[3]{10+6\sqrt{3}}\)
d) \(\dfrac{4+2\sqrt{3}}{\sqrt[3]{10+6\sqrt{3}}}\)
e) E=\(\sqrt[3]{2+10\sqrt{\dfrac{1}{27}}}+\sqrt[3]{2-10\sqrt{\dfrac{1}{27}}}\)
Tính:a)left(dfrac{1}{2}sqrt[3]{9}-2sqrt[3]{3}+3sqrt[3]{dfrac{1}{3}}right):2sqrt[3]{dfrac{1}{3}}
b)left(sqrt[3]{4}+1right)^3-left(sqrt[3]{4}-1right)^3
c)left(12sqrt[3]{2}+sqrt[3]{16}-2sqrt[3]{2}right)left(5sqrt[3]{4}-3sqrt[3]{dfrac{1}{2}}right)
Đọc tiếp
Tính:a)\(\left(\dfrac{1}{2}\sqrt[3]{9}-2\sqrt[3]{3}+3\sqrt[3]{\dfrac{1}{3}}\right)\):\(2\sqrt[3]{\dfrac{1}{3}}\)
b)\(\left(\sqrt[3]{4}+1\right)^3\)-\(\left(\sqrt[3]{4}-1\right)^3\)
c)\(\left(12\sqrt[3]{2}+\sqrt[3]{16}-2\sqrt[3]{2}\right)\)\(\left(5\sqrt[3]{4}-3\sqrt[3]{\dfrac{1}{2}}\right)\)
tính
a. \(\dfrac{\sqrt[3]{125}.\sqrt[3]{\dfrac{16}{10}}.\sqrt[3]{-0,5}}{\sqrt[3]{4}+\sqrt[3]{2}+1}\)
b.\(\sqrt[]{3+\sqrt[]{5}+\sqrt[]{10+6\sqrt[]{5}}}\)
21 tháng 9 2023 lúc 18:00
Tính: (\(\sqrt[3]{\dfrac{1}{9}}+4\sqrt[3]{\dfrac{1}{72}}-\sqrt[3]{4}\) )(\(\sqrt[3]{72}+\sqrt[3]{96}+\sqrt[3]{128}\))
1.Chứng minh:\(\dfrac{a+\sqrt{2+\sqrt{5}.}\sqrt{\sqrt{9-4\sqrt{5}}}}{3\sqrt{2-\sqrt{5}}.\sqrt[3]{\sqrt{9+4\sqrt{5}-}3\sqrt{a^2}+\sqrt[3]{a}}}\)=\(-\sqrt[3]{a}-1\)
2.Rút gọn: \(\left(\dfrac{a^3\sqrt[]{a}-2a^3\sqrt{b}+\sqrt[3]{a^2}-\sqrt[3]{b}}{\sqrt[3]{a^2-\sqrt[3]{ab}}}+\dfrac{\sqrt[3]{a^2b}-\sqrt[3]{ab^2}}{\sqrt[3]{a}-\sqrt[3]{b}}\right)1\dfrac{1}{\sqrt[3]{a^2}}\)
thực hiện phép tính sau
\(\dfrac{1}{\sqrt[3]{9}-\sqrt[3]{6}+\sqrt[3]{4}}-\dfrac{\sqrt[3]{3}+\sqrt[3]{2}}{5}\)
27 tháng 9 2023 lúc 20:27
So sánh:M=\(\sqrt[3]{7+5\sqrt{2}}\)+\(\sqrt[3]{7-5\sqrt{2}}\) và N=\(\dfrac{4}{\sqrt[3]{9}}\)
giúp em với ạ tính
\(\sqrt[3]{125}.\sqrt[3]{\dfrac{16}{10}}.\sqrt[3]{-0,5}\)
Tính
a.A=\(\sqrt[3]{2+\sqrt{5}}+\sqrt[3]{2-\sqrt{5}}\)
b.B=\(\sqrt[3]{3+\sqrt{9+\dfrac{125}{7}}}-\sqrt[3]{-3+\sqrt{9+\dfrac{125}{7}}}\)
c.C=\(\sqrt[3]{26+15\sqrt{3}}.\left(2-\sqrt{3}\right)+\sqrt[3]{9+\sqrt{80}}+\sqrt[3]{9-\sqrt{80}}\)