Question

So sánh :

Answer 1

Ta có :\(\left(100^{99}+99^{99}\right)^{100}>\left(100^{99}+99^{99}\right)^{99}\times100^{99}\)

\(=\left(100^{100}+100\times99^{99}\right)^{99}>\left(100^{100}+99^{100}\right)^{99}\)

\(\Rightarrow A>B\)

Vậy \(A>B\)