1.So sánh: A=\(\frac{1}{2^1}+\frac{1}{2^2}+...+\frac{1}{2^{49}}+\frac{1}{2^{50}}\) và 1:
1.So sánh: A=\(\frac{1}{2^1}+\frac{1}{2^2}+...+\frac{1}{2^{49}}+\frac{1}{2^{50}}\) và 1:
C=\(\frac{1}{3}+\frac{1}{3^2}+...+\frac{1}{3^{99}}< -\frac{1}{2}\)
D=\(\left(\frac{1}{2^2}-1\right).\left(\frac{1}{3^2}-1\right).\left(\frac{1}{4^2}-1\right)...\left(\frac{1}{100^2}-1\right)< -\frac{1}{2}\)
A=\(\left[\frac{1}{100}-1^2\right].\left[\frac{1}{100}-\left(\frac{1}{2}\right)^2\right].\left[\frac{1}{100}-\left(\frac{1}{3}\right)^2\right]....\left[\frac{1}{100}-\left(\frac{1}{20}\right)^2\right]\)
Mọi người giúp em với ạ :'(
Thực hiện phép tính
a) \(\left[6.\left(-\frac{1}{3}\right)^2-3.\left(-\frac{1}{3}\right)+1\right]:\left(-\frac{1}{3}-1\right)\)
b) \(\frac{\left(\frac{2}{3}\right)^3.\left(-\frac{3}{4}\right)^2.\left(-1\right)^{2003}}{\left(\frac{2}{5}\right)^2.\left(-\frac{5}{12}\right)^3}\)
1)\(\frac{27^4.9^3}{81^2}\)
2)\(\left(\frac{1}{5^{^{ }}}\right)^{2002}.\left(-5\right)^{2000}\)
3)\(\frac{4^{11}.4^5}{2^{31}}\)
4)\(3^2.\frac{1}{243}.81^2.\frac{1}{3^2}\)
5)\(4^2.\frac{25^2}{2^3.5^2}+32.125\)
1/Tính
a)
\(\frac{2}{5}+\frac{1}{5}\times\left(\frac{3}{4}\right)\)
b)\(\frac{5}{12}\times\left(\frac{-3}{4}\right)+\frac{7}{12}\times\left(\frac{-3}{4}\right)\)
c)\(\frac{2^{15}\times9^4}{6^6\times8^3}\)
2/Tìm x biết:
a)\(\frac{5}{7}+\frac{2}{7}x=1\)
b)0,2+\(\left|x-1,3=1,5\right|\)
c)\(2^x+5=37\)
d)\(2^x+2^{x+1}=48\)
Bài 1: Tính
1/ x: -\(\frac{-1}{2}\)=\(\frac{-1}{2}\)
2/ (\(\frac{3}{4}\))5*x=(\(\frac{5}{4}\))7
3/ \(\frac{16}{2^n}\)=2
4/ \(\frac{-3^n}{81}\)=-27
MAI TỚ CẦN GẤP CÁC CẬU GIÚP TỚ NHÉ! CẢM ƠN MN TRƯỚC
Tìm x,y biết
a) \(x^4+\left(y-\frac{1}{10}\right)^6=0\)
b) (\(\frac{1}{2}x-5\))^20+(\(y^2-\frac{1}{4}\))^10\(\le\)0