Question

So sánh A=\(\dfrac{2004^{2005}+1}{2004^{2005}-2004}\) và \(\dfrac{2004^{2005}}{2004^{2005}+2004}\)

Giải nhanh giúp mình!THANKS

Answer 1

\(A=\dfrac{2004^{2005}+1}{2004^{2005}-2004}>1>\dfrac{2004^{2005}}{2004^{2005}+2004}=B\)

Vậy A > B

Answer 2

Ta có :

\(\dfrac{2004^{2005}+1}{2004^{2005}-2004}>1>\dfrac{2004^{2005}}{2004^{2005}+2004}\)

\(\Rightarrow\) \(A>1>B\)

\(\Rightarrow\) \(A>B\)