Bài 8: Rút gọn biểu thức chứa căn bậc hai
Các câu hỏi tương tự
Đề bài: Thực hiện phép tính :
a) left(frac{2sqrt{3}-sqrt{6}}{sqrt{8}-2}-frac{sqrt{216}}{3}right).frac{1}{sqrt{6}}
b) left(frac{sqrt{14}-sqrt{7}}{1-sqrt{2}}-frac{sqrt{15}-sqrt{5}}{1-sqrt{3}}right):frac{1}{sqrt{7}+sqrt{5}}
c) frac{sqrt{5+2sqrt{6}}+sqrt{8-2sqrt{15}}}{sqrt{7+2sqrt{10}}}
Giúp em với ạ, em cảm ơn !
Đọc tiếp
Đề bài: Thực hiện phép tính :
a) \(\left(\frac{2\sqrt{3}-\sqrt{6}}{\sqrt{8}-2}-\frac{\sqrt{216}}{3}\right).\frac{1}{\sqrt{6}}\)
b) \(\left(\frac{\sqrt{14}-\sqrt{7}}{1-\sqrt{2}}-\frac{\sqrt{15}-\sqrt{5}}{1-\sqrt{3}}\right):\frac{1}{\sqrt{7}+\sqrt{5}}\)
c) \(\frac{\sqrt{5+2\sqrt{6}}+\sqrt{8-2\sqrt{15}}}{\sqrt{7+2\sqrt{10}}}\)
Giúp em với ạ, em cảm ơn !
Rút gọn:
1) \(\dfrac{16-6\sqrt{7}}{\sqrt{7}-3}\)
2) \(\dfrac{\left(\sqrt{3}-\sqrt{2}\right)^2+4\sqrt{6}}{\sqrt{3}+\sqrt{2}}\)
3) \(\dfrac{\left(\sqrt{3}+2\sqrt{5}\right)^2-8\sqrt{15}}{\sqrt{6}-2\sqrt{10}}\)
Giúp em với ạ. Help mee !!!
tính giá trị biểu thức :
a, \(\left(\sqrt{28}+2\sqrt{14}+\sqrt{7}\right)\sqrt{7}-\left(7+\sqrt{2}\right)^2\)
b, \(\sqrt{\dfrac{5}{2}}+\dfrac{\sqrt{2}}{\sqrt{3}+\sqrt{5}}\)
c, \(\dfrac{8+2\sqrt{15}}{\sqrt{5}+\sqrt{3}}+\dfrac{7-2\sqrt{10}}{\sqrt{5}-\sqrt{2}}\)
d,\(\dfrac{3+4\sqrt{3}}{\sqrt{6}+\sqrt{2}-\sqrt{5}}\)
1. Asqrt{4+sqrt{7}} +sqrt{4-sqrt{7}}
2. B dfrac{sqrt{sqrt{7-sqrt{3}}-sqrt{7+sqrt{3}}}}{sqrt{7-sqrt{2}}}
3. Csqrt{6+2sqrt{2cdotsqrt{3-sqrt{4+2sqrt{3}}}}}
4. Dsqrt{5}-sqrt{3-sqrt{29-12sqrt{5}}}
5 Edfrac{1+sqrt{5}}{sqrt{2}+sqrt{3}+sqrt{5}} +dfrac{1-sqrt{5}}{sqrt{2}-sqrt{3-sqrt{5}}}
6. so sánh Cho Asqrt{11+sqrt{96}}
B dfrac{2sqrt{2}}{1+sqrt{2-sqrt{3}}} so sánh A và b
Đọc tiếp
1. A=\(\sqrt{4+\sqrt{7}}\) +\(\sqrt{4-\sqrt{7}}\)
2. B= \(\dfrac{\sqrt{\sqrt{7-\sqrt{3}}-\sqrt{7+\sqrt{3}}}}{\sqrt{7-\sqrt{2}}}\)
3. C=\(\sqrt{6+2\sqrt{2\cdot\sqrt{3-\sqrt{4+2\sqrt{3}}}}}\)
4. D=\(\sqrt{5}-\sqrt{3-\sqrt{29-12\sqrt{5}}}\)
5 E=\(\dfrac{1+\sqrt{5}}{\sqrt{2}+\sqrt{3}+\sqrt{5}}\) +\(\dfrac{1-\sqrt{5}}{\sqrt{2}-\sqrt{3-\sqrt{5}}}\)
6. so sánh Cho A=\(\sqrt{11+\sqrt{96}}\)
B= \(\dfrac{2\sqrt{2}}{1+\sqrt{2-\sqrt{3}}}\) so sánh A và b
Rút gọn:
a) \(A=\sqrt{4+2\sqrt{2}}\sqrt{2+2+\sqrt{2}}.\sqrt{2-2+\sqrt{2}}\)
b) \(B=\left(\sqrt{2}-\sqrt{3+\sqrt{5}}\right)\sqrt{2}+2\sqrt{5}\)
c) \(C=\left(\sqrt{14}-\sqrt{10}\right)\left(\sqrt{6}+\sqrt{35}\right)\)
d) \(D=\sqrt{11-4\sqrt{7}}-\sqrt{2}.\sqrt{8+3\sqrt{7}}\)
Bài 1 : rút gọn
a, sqrt{8}-3sqrt{32}+sqrt{72}
b, 6sqrt{12}-sqrt{20}-2sqrt{27}+sqrt{125}
c, 3sqrt{112}-7sqrt{216}+4sqrt{54}-2sqrt{252}-3sqrt{96}
bài 2 : rút gọn
1, 3sqrt{3}left(3+2sqrt{6}-sqrt{33}right)
2, sqrt{2}left(sqrt{8}-sqrt{32}+3sqrt{18}right)
3, left(2sqrt{2}-3sqrt{7}+5sqrt{63}right)sqrt{112}
4, (5sqrt{6}-4sqrt{10}+7sqrt{30}):sqrt{2}
5, left(5sqrt{3}+3sqrt{5}right):sqrt{15}
6, left(4sqrt{27}-2sqrt{48}-5sqrt{75}right):2sqrt{3}
7, left(1+sqrt{3}-sqrt{2}right).left(1+sqrt{3}+sqr...
Đọc tiếp
Bài 1 : rút gọn
a, \(\sqrt{8}-3\sqrt{32}+\sqrt{72}\)
b, \(6\sqrt{12}-\sqrt{20}-2\sqrt{27}+\sqrt{125}\)
c, \(3\sqrt{112}-7\sqrt{216}+4\sqrt{54}-2\sqrt{252}-3\sqrt{96}\)
bài 2 : rút gọn
1, \(3\sqrt{3}\left(3+2\sqrt{6}-\sqrt{33}\right)\)
2, \(\sqrt{2}\left(\sqrt{8}-\sqrt{32}+3\sqrt{18}\right)\)
3, \(\left(2\sqrt{2}-3\sqrt{7}+5\sqrt{63}\right)\sqrt{112}\)
4, \((5\sqrt{6}-4\sqrt{10}+7\sqrt{30}):\sqrt{2}\)
5, \(\left(5\sqrt{3}+3\sqrt{5}\right):\sqrt{15}\)
6, \(\left(4\sqrt{27}-2\sqrt{48}-5\sqrt{75}\right):2\sqrt{3}\)
7, \(\left(1+\sqrt{3}-\sqrt{2}\right).\left(1+\sqrt{3}+\sqrt{2}\right)\)
các bạn ơi ! giúp mik vs đi !!!!!!!!!!!!!!
1. Asqrt{4+sqrt{ }7}+ sqrt{4-sqrt{ }7} 2. Bdfrac{sqrt{sqrt{7-sqrt{3}}}-sqrt{sqrt{7+sqrt{3}}}}{sqrt{sqrt{7}-sqrt{2}}} 3. Csqrt{6+2sqrt{2cdotsqrt{3-sqrt{4+2sqrt{3}}}}} 4. Dsqrt{5}-sqrt{3-sqrt{29-12sqrt{5}}}...
Đọc tiếp
1. A=\(\sqrt{4+\sqrt{ }7}\)+ \(\sqrt{4-\sqrt{ }7}\) 2. B=\(\dfrac{\sqrt{\sqrt{7-\sqrt{3}}}-\sqrt{\sqrt{7+\sqrt{3}}}}{\sqrt{\sqrt{7}-\sqrt{2}}}\) 3. C=\(\sqrt{6+2\sqrt{2\cdot\sqrt{3-\sqrt{4+2\sqrt{3}}}}}\) 4. D=\(\sqrt{5}-\sqrt{3-\sqrt{29-12\sqrt{5}}}\) 5. so sánh Cho A=\(\sqrt{11+\sqrt{96}}\) B=\(\dfrac{2\sqrt{2}}{\sqrt{1+\sqrt{2-\sqrt{3}}}}\) so sánh A và B
Rút gọn :
a) \(\sqrt{4-\sqrt{7}}-\sqrt{4+\sqrt{7}}\)
b) \(\dfrac{\sqrt{3}+\sqrt{11+6\sqrt{2}}-\sqrt{5+2\sqrt{6}}}{\sqrt{2}+\sqrt{6+2\sqrt{5}}-\sqrt{7+2\sqrt{10}}}\)
Rút gọn :
1, sqrt{8}-3sqrt{32}+sqrt{72}
2, 6sqrt{12}-sqrt{20}-2sqrt{27}+sqrt{125}
3 , 3sqrt{112}-7sqrt{216}+4sqrt{54}-2sqrt{252}-3sqrt{96}
4, 3sqrt{3}left(3+2sqrt{6}-sqrt{33}right)
6, sqrt{2}left(sqrt{8}-sqrt{32}+3sqrt{18}right)
7, (5sqrt{6}-4sqrt{10}+7sqrt{30}):sqrt{2}
8, left(2sqrt{28}-3sqrt{7}+5sqrt{63}right)sqrt{112}
9, left(5sqrt{3}+3sqrt{5}right):sqrt{15}
10, left(4sqrt{27}-2sqrt{48}-5sqrt{75}right):2sqrt{3}
11, left(1+sqrt{3}-sqrt{2}right).left(1+sqrt{3}+sqrt{2}right)
các bạn...
Đọc tiếp
Rút gọn :
1, \(\sqrt{8}-3\sqrt{32}+\sqrt{72}\)
2, \(6\sqrt{12}-\sqrt{20}-2\sqrt{27}+\sqrt{125}\)
3 , \(3\sqrt{112}-7\sqrt{216}+4\sqrt{54}-2\sqrt{252}-3\sqrt{96}\)
4, \(3\sqrt{3}\left(3+2\sqrt{6}-\sqrt{33}\right)\)
6, \(\sqrt{2}\left(\sqrt{8}-\sqrt{32}+3\sqrt{18}\right)\)
7, \((5\sqrt{6}-4\sqrt{10}+7\sqrt{30}):\sqrt{2}\)
8, \(\left(2\sqrt{28}-3\sqrt{7}+5\sqrt{63}\right)\sqrt{112}\)
9, \(\left(5\sqrt{3}+3\sqrt{5}\right):\sqrt{15}\)
10, \(\left(4\sqrt{27}-2\sqrt{48}-5\sqrt{75}\right):2\sqrt{3}\)
11, \(\left(1+\sqrt{3}-\sqrt{2}\right).\left(1+\sqrt{3}+\sqrt{2}\right)\)
các bạn ơi ! giúp mik với đi !